(1) Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as
old as Sonu. How old are Nuri and Sonu?
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✬ Nuri's age = 50 years ✬
✬ Sonu's age = 20 years ✬
Step-by-step explanation:
Given:
- Five years ago , Nuri was thrice as old as Sonu.
- After ten years, Nuri will be twice as old as Sonu.
To Find:
- How old are Nuri and Sonu ?
Solution: Let Nuri's and Sonu's present ages be x & y years respectively.
➭ Case 1st ( Five years ago)
- Nuri's age = (x – 5) years.
- Sonu's age = (y – 5) years.
A/q, 5 years ago Nuri was thrice as old as Sonu.
(x – 5) = 3(y – 5)
x – 5 = 3y – 15
x = 3y – 15 + 5
x = 3y – 10.....(1)
➭ Case 2nd ( Ten years later )
- Nuri's age = (x + 10) years.
- Sonu's age = (y + 10) years.
A/q, 10 years later Nuri will twice as old as Sonu.
(x + 10) = 2(y + 10)
x + 10 = 2y + 20
x = 2y + 20 – 10
x = 2y + 10.......(2)
★ Put value of x in equation 2 from 1 ★
➙ 3y – 10 = 2y + 10
➙ 3y – 2y = 10 + 10
➙ y = 20 years
Hence, Age of Sonu is y = 20 years.
★ Put the value of y in equation 1 ★
➙ x = 3y – 10
➙ x = 3(20) – 10
➙ x = 50 years
Hence, Age of Nuri is x = 50 years.
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