Question

1. FOCAL LENGTH OF A CONVERGING LENS IS 15CM AN OBJECT IS PLACED AT 25CM FROM THE LENS FIND POSITION SIZE AND NATURE OF IMAGE GIVEN OBJECT SIZE IS 6CM..​

Answer 1

Explanation:

Focal length (f ) = -15 cm

Distance of image (v) = -10 cm

1

v

–

1

u

=

1

f

1/u = -(1/10) – (1/- 15)

1/u =1/15 – 1/10

1/u = -0.033

u = -30 cm

So, the object is placed 30 cm away from the concave lens.