Question

1) For a polynomial p(m)= 9m3

- 4m2

+8m+4 ,find the value of p(2) +p(-2)​

Answer 1

Step-by-step explanation:

p(m)=

$9 {m}^{3} - 4 {m}^{2} + 8m + 4$

p(2)=

$9 {(2)}^{3} - 4 {(2)}^{2} + 8 \times 2 + 4$

=72 - 16 + 16 + 4

= 76

p(-2)=

$9 {( - 2)}^{3} - 4 {( - 2)}^{2} + 8 \times ( - 2) + 4$

=

$9 \times ( - 8) - 4 \times4 - 16 + 4$

$= - 72 - 16 - 16 + 4$

= -104 + 4

= -100

therefore

p(2) + p(-2) =

76 + (-100) = -24