Question

1.For a single-phase transformer with 250 primary turns and 50 secondary turns, connected across a 1500 Volts, 50HZ supply, the maximum value of flux is​

Answer 1

Answer:

option a is a correct answer 1 wb

Answer 2

Given:

For a single-phase transformer

Primary turns = 250

Secondary turns = 50

Voltage = 1500

To Find:

the maximum value of flux

Explanation:

E=N(dΦ/dt)=NωΦ cos(ωt)

E =NωФ

E =NωΦ/√2

Now,

​E(rms0=NωΦ/√2

=N2πfΦ/√2 = 4.44NfΦ

Φ= E(rms)/4.44Nf = 1500/(4.44.25.50)

  =0.027 Wb

​Answer =0.027Wb( maximum flux)