Question

1. For adiabatic expansion of a monoatomic
perfect gas, the volume increases by 2.4%.
The percentage decrease in pressure is
1) 2.4 % 2) 4.0% 3) 4.8 % 4) 7.1 %​

Answer 1

Answer: option d

Explanation:

 from the above question we know that its an adiabatic process and

PV^gamma = constant  

gamma for monoatomic gas is 1.66.

volume increased by 2.4% means

V2 =V1 +2.4%of V1

V2=1.024V1

putting these value on the above expression you will get-

P1/P2=1.04

so %decrease in pressure would be 4%

Answer 2

answer:::::::--- is.

4.0%