Question

1
For some integer m, every odd integer is of the
form
[1]
(1) 2m + 1
(2) 2m
(3) m+ 1
(4) m

Answer 1

ANSWER:

• Every odd number is in the form of (2m+1).

GIVEN:

• A positive integer 'm'.

TO FIND:

• Odd integer

GIVEN:

• 'n' is a positive integer which is divided by 2 we get some quotient 'm' and remainder 'r'
• Where r = 0 and 1

• n = 2m+r ........(i)
• putting r = 0 in eq (i)

• n = 2m+0
• m = 2m ( Divisible by 2)
• It is an even number.

• putting r = 1 in eq(i)
• n = 2m+1 ( not divisible by 2)
• It is an odd number.

So every odd number is in the form of (2m+1). where m is any positive integer.

Every even number is in the form of (2m) where m is any positive integer.

CORRECT OPTION : (1)☑️☑️

Answer 2

Answer:

correct answer is

2m+1

marks as brain list