Physics, asked by Sanchari1370, 10 hours ago

1 for the emitter follower in fig. 11.2, vcc = 15 v, vcesat = 0.2 v, vbe = 0.7 v and constant, and is very high. Find the value of r that will establish a bias current sufficiently large to allow the largest possible output signal swing for rl = 1 k. Determine the resulting output signal swing and the minimum and maximum emitter currents for q1. Solution

Answers

Answered by anjalitripathi4125

To find the value of resistor R that will establish a bias current sufficiently large to allow the largest possible output signal swing for RL = 1kΩ, we need to follow these steps:

Determine the bias current (Ibias):

The bias current is determined by the voltage drop across resistor R and the value of R itself.

We can use Ohm's Law: V = I * R, where V is the voltage drop across R and I is the bias current.

The voltage drop across R is equal to Vcc - Vcesat, where Vcc is 15V and Vcesat is 0.2V.

So, the bias current can be calculated as: Ibias = (Vcc - Vcesat) / R.

Calculate the maximum output swing (Vout_swing):

The maximum output swing is limited by the voltage available at the collector of Q1.

The maximum voltage at the collector is Vcc - Vcesat.

Therefore, the maximum output swing is equal to 2 * (Vcc - Vcesat).

Determine the minimum and maximum emitter currents (Ie_min and Ie_max):

The emitter current is equal to the bias current (Ibias) plus the current flowing through RL.

The minimum emitter current (Ie_min) occurs when the output swing is at its maximum and RL is at its lowest value.

The maximum emitter current (Ie_max) occurs when the output swing is at its minimum and RL is at its highest value.

Ie_min = Ibias + (Vout_swing / RL_max), where RL_max is the maximum value of RL.

Ie_max = Ibias + (Vout_swing / RL_min), where RL_min is the minimum value of RL.

By following these steps, we can determine the value of R, the output swing (Vout_swing), and the minimum and maximum emitter currents (Ie_min and Ie_max) for Q1.