Question

1. For what value of k. (-4) is
x² - x-(2k + 2) a zero of the polynomial? ​

Answer 1

$\huge\color{cyan}\boxed{\colorbox{black}{⚛solution:-}}$

x²-x-(2k+2)=(-4)²-(-4)

= -(2k+2)=0 =20-2k-2=0

18-2k=0

Hence K = 9 (Answer)

_______________________________________