Question

1
For what value of k, the pair of linear equations 3x+y=3 and 6x+y=8 does
not have a solution.​

Answer 1

Hey Mate!

Here we have,

3x+y-3=0 .... eq i-

6x+ky-8=0 .... eq ii-

a1=3 , b1=1 , c1=(-3)

a2=6 , b2=k , c2=(-8)

If a1/a2 = b1/b2 ≠ c1/c2 has no solutions

3/6 = 1/k ≠ (-3)/(-8)

3/6 = 1/k

3k = 6 ....( cross multiplication )

k = 6/3

k = 2

Thus the value of k for which the pair of linear equations 3x+y=3 and 6x+y=8 does not have a solution is, 2.

Hope it helps :-)

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