Question

1. For what value of P the quadratic equation 16x^2 + Px + 1 has equal
real roots ?​

Answer 1

Answer:

Answer is 8

Step-by-step explanation:

See answer in above picture

Answer 2

Answer:

8

Step-by-step explanation:

FOR THE EQUAL ROOT THE DISCRIMINANT MUST BE EQUAL TO ZERO

B²-4AC=0

P²-4*16*1=0

P²-64=0

P²=64

P=8

THANKS!!!

HOPE YOU UNDERSTAND THE EXPLANATION