Math, asked by gayathribandhakavi5, 10 months ago

1. For what value of P the quadratic equation 16x2 + Px + 1 has equal
real roots​

Answers

Answered by raju35652
10

Step-by-step explanation:

16x²+Px+1=0

given condition

b²-4ac=0

p2-4(16)1=0

p²-64=0

p²=64

p=8

Answered by harendrachoubay
0

The value of "P is equal to 8".

Step-by-step explanation:

The given quadratic equation:

16x^2+Px+1=0

Here, a = 16, b = P and c = 1

To find, the value of P = ?

D=b^{2} -4ac

=P^{2} -4(16)(1)

=P^{2} -64

Given by question,

The roots are equal, D = 0

P^{2} -64=0

P^{2}=64

P^{2}=8^{2}

⇒ P = 8

∴ The value of P = 8

Hence, the value of "P is equal to 8".

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