Question

1. For what value of P the quadratic equation 16x2 + Px + 1 has equal
real roots​

Answer 1

Step-by-step explanation:

16x²+Px+1=0

given condition

b²-4ac=0

p2-4(16)1=0

p²-64=0

p²=64

p=8

Answer 2

The value of "P is equal to 8".

Step-by-step explanation:

The given quadratic equation:

$16x^2+Px+1=0$

Here, a = 16, b = P and c = 1

To find, the value of P = ?

∴ $D=b^{2} -4ac$

$=P^{2} -4(16)(1)$

$=P^{2} -64$

Given by question,

The roots are equal, D = 0

$P^{2} -64=0$

⇒ $P^{2}=64$

⇒ $P^{2}=8^{2}$

⇒ P = 8

∴ The value of P = 8

Hence, the value of "P is equal to 8".