Question

1) Force experienced by charge 'q' moving with
velocity 'v' in a magnetic field 'B' is given by
F=qvB. Find the dimensions of magnetic field.​

Answer 1

Answer:

f=qvB

B=F/q.v.

B=mLT^-2/LT^-1×A×T

B=MAT^-2

so dimension is m^1,A^1,t^-2 (1,1,-2)

Answer 2

Answer:[MT^-2A^-1]

Explanation:B=F/qv

F=[MLT^-2]

q=[AT]

v=[LT^-1]

Putting all the values

B=[MT^-2A^-1]