Question

(1) Form a quadratic equation whose roo
ts are 3/2 and 4/5​

Answer 1

Answer:

x^{2}-

Step-by-step explanation:

quadratic eqn =$k{x^2-(sum of roots)x+product of roots}$

where k is any constant and let k is the lcm of denominators of coefficients nd constant term

sum of roots = 3/2+4/5=23/10

product of roots =3/2*4/5=12/10

then eqn is

$k[x^{2}-(23/10)x+12/10]$

let k =10

then eqn is

$10x^2-23x+12$

Answer 2

Answer:

Step-by-step explanation: