Question

1) Form new equations by carrying out the
action (given in brackets) on both sides
of the equation.
(i) 2x + 3 = 13 (Multiply by 2)
(ii) 3y - 3 = 21 (Add 5)
(iii) 5x + 14 = 24 (Subtract 6)​

Answer 1

Answer:

(i) Let the required number be x.

So, five times the number will be 5x.

∴ 5x = 40

(ii) Let the required number be x.

So, when it is increased by 8, we get x + 8.

∴ x + 8 = 15

(iii) Let the required number be x.

So, when 25 exceeds the number, we get 25 − x.

∴ 25 − x = 7

(iv) Let the required number be x.

So, when the number exceeds 5, we get x − 5.

∴ x − 5 = 3

(v) Let the required number be x.

So, thrice the number will be 3x.

∴ 3x − 5 = 16

(vi) Let the required number be x.

So, 12 subtracted from the number will be x − 12.

∴ x − 12 = 24

(vii) Let the required number be x.

So, twice the number will be 2x.

∴ 19 − 2x = 11

(viii) Let the required number be x.

So, the number when divided by 8 will be x8.

∴ x8 = 7

(ix) Let the required number be x.

So, four times the number will be 4x.

∴ 4x − 3 = 17

(x) Let the required number be x.

So, 6 times the number will be 6x.

∴ 6x = x + 5

Step-by-step explanation:

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