Question

(1) four equal circles,each of radius '24' touch one another. find the area between them
(2) four equal circles are described about the four corners of a square so that each circle touches two of the others. find the area of the space enclosed between the circumferences of the circles, each side of the square measuring 6/7a^2
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Answer 1

Answer:

(1)..............493.72

Step-by-step explanation:

it becomes the square of side 48

area of square=48²

                     =2304

area of 4 sector of making angle 90° =(4*90/360)*(πr²)

                                                        =(22*24*24)/7

                                                        =1810.28

area betweem them=2304-1810.28

                              =493.72