Question

1. four like charges of 30 µc each are located at the four corners of a square, the diagonal of which is 8 m. find the force on a 150 charge located at 3 m above the centre of the square.

Answer 1

Answekesa laga Mera majak

Answer 2

The force acting on the point charge due to the four charges located at the corners of the square is $2.16 * 10^-5 N.$

• The force acting on a point charge due to other charges can be calculated using Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

• To find the force on the point charge located at (0,0,3), we need to calculate the force acting on it due to each of the four charges located at the corners of the square.
• Let's consider one of the charges located at (4,4,0). The magnitude of the force can be calculated using the following formula:

F = $(k * q1 * q2) / r^2$

Where k is Coulomb's constant ($8.99 * 10^9 Nm^2/C^2),$

q1 is the charge of the point charge (150 µC),

q2 is the charge at the corner of the square (30 µC),

and r is the distance between them

$(\sqrt((4-0)^2 + (4-0)^2 + (3-0)^2) = 5 m).$

So, the magnitude of the force can be calculated as:

F = $(8.99 * 10^9 Nm^2/C^2) * (150 * 10^-6 C) * (30 * 10^-6 C) / (5 m)^2$

= $5.39 * 10^-6 N$

Since the four charges at the corners of the square are identical, the total force acting on the point charge is

$4 * 5.39 * 10^-6 N = 2.16 * 10^-5 N.$

Therefore, the force acting on the point charge due to the four charges located at the corners of the square is $2.16 * 10^-5 N.$

Similar Problems

brainly.in/question/30219

brainly.in/question/5921220

#SPJ3