Question

1. From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a
rectangle of length 3 cm and breadth lcm are removed (as shown in the adjoining
figure). Find the area of the remaining sheet. (Takenπ= 22/7)
​

Answer 1

Answer:

AREA OF CIRCULAR CARD := π × r^2

:= 22 ×14 ×14

7

:=616 cm^2

AREA OF TWO CIRCLE:= 2× π r^2

:=2×22×3.5×3.5

7

:=77 cm^2

AREA OF RECTANGLE := l ×b

:=3 ×1

:=3 cm^2

AREA OF REMAINING SHEET := AR. OF CICULAR SHEET - AR. OF TWO CIRCLE - AR. OF RECTANGLE.

:= 616-77-3

:=536 cm^2

Answer 2

$\large{\bf{\blue{\underline{\underline{Hi....!! }}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = </p><p>⠀⠀⠀⠀\: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$