(1) From a point in the interior of an equilateral triangle, perpendiculars are drawn on the three sides. If the lengths of the perpendiculars are a, b and c, find the altitude of the triangle. please answer 25 points
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Answer:
Step-by-step explanation:
Area of ∆ABC = Area of ∆APB + Area of ∆BPC + Area of ∆CPA
4
3
a
2
=
2
1
[PS×AB×PQ×BC×PR×AC]
⇒
4
3
a
2
=
2
1
×a×[14×10×6]
⇒
4
3
a
2
=
2
1
×a×30
⇒
4
3
a
2
=15a
⇒a=
3
15×4
=
3
60
cm
Area of triangle ABC =
4
3
×
3
60
×
3
60
=300
3
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