Question

1. From a rope 11 m long, two pieces of lengths 13/5 m and 33/10 m are cut off. What is the length of the remaining rope?

2. A drum full of rice weighs 241/6 kg. If the empty drum weighs 55/4 kg, find the weight of rice in the drum.

3. A basket contains three types of fruits weighing 58/3 kg in all. If 73/9 kg of these be apples, 19/6 kg be oranges and the rest pears. What is the weight of the pears in the basket?

Answer 1

3. See above

1. Total 11 Meters

13/5 m, 33/10 m are cut off. what is the remaining?

first of all, try to get a common multiple on the denominator of both the fractions to make it easier for you to add both the lengths.

so 13/5 both numerator and denominator is multiplied by 2 to get the denominator as 10 , which equals 26/10

now 26/10 rope piece and the other rope piece 33/10 both have the same denominator, so when added

26/10 + 33/10 = 59/10,

so 59/10 meters(5.9M) of rope has been cut off, now subtract this length from 11 meters initial rope length.

so 11 M - 5.9 M = 5.1 M remaining

or 11 x 10/10 = 110/10

110/10 - 59/10 = 51/10 (5.1)

However you do it the answer will be 5.1 Meters

2.full drum weighs 241/6 kilograms.

empty drum weighs 55/4 kilogrms.

rice will weight 241/6 - 55/4 kilograms.

place both fractions under a common denominator to get:

(4 * 241) / 24 - (6 * 55) / 24

combine like fractions to get:

((4 * 241) - (6 * 55)) / 24

simplify to get:

(964 - 330) /24

combine like terms to get:

634 / 24

simplify to get:

317 / 12

that's your answer.

in mixed fraction format, it will be equal to 26 5/12.

Answer 2

Answer:

please see the attachment...

I hope this helps you...