Question

1. From the following polynomials find out
which of them has (x - 1) as a factor :
(1)x - 7x2 + 14x-8 (2) x2 + 4x2 + x-6
(3)x3 + 6x2 - 9x - 14 (4) 2x + 5x2 - X-6​​

Answer 1

Answer:

x - 1=0

x=1

Step-by-step explanation:

(1)x - 7x2 + 14x-8

1-7(1)+14(1)-8

1-7+14-8

-6+6

=0

(2) x2 + 4x2 + x-6

(1)+4(1)+1-6

1+4+1-6

6-6

=0

(3)x3 + 6x2 - 9x - 14

(1)+6(1)-9(1)-14

1+6-9-14

1-3-14

1-17

=-16

(4) 2x + 5x2 - X-6

2(1)+5(1)-1-6

2+5-1-6

7-7

=0