Math, asked by anikaitatwal2005, 8 months ago


(1) ਹੇਠ ਦਿੱਤੀਆਂ ਸੰਖਿਆਵਾਂ ਵਿਚੋਂ ਕਿਹੜੀ ਸੰਖਿਆ ਅਪਰਿਮੇਯ ਸੰਖਿਆ ਹੈ?From the given numbers which is an irrational number?दी गई संख्याओं में से, कौन सी अपरिमेय संख्या है? *
1/1
(3+√23)-√23
2-√5
√25
(2√7)/(7√7)​

Answers

Answered by SantoshB
0

last option is irrational (2√7)/(7√7)

Answered by arshikhan8123
0

Concept:

Real numbers that cannot be expressed as a straightforward fraction are referred to be irrational numbers. It can't be stated as a ratio, as p/q, where p and q are both integers, q≠0. It defies logic in terms of numbers.

Ordinarily, irrational numbers are denoted as R\Q, where the backward slash symbol stands for "set minus." The difference between a set of real numbers and a set of rational numbers can alternatively be written as R - Q.

These values require some difficult computations. For instance, √5, √11, √21, and other numbers are illogical. When doing arithmetic operations with such numbers, we must first determine the values under root. These values might occasionally occur again.

Given:

1/1

(3+√23)-√23

2-√5

√25

(2√7)/(7√7)​

Find:

Which of these is a irrational number

Solution:

a) 1/1  = 1

It is a rational number

b) 3+√23 -√23 =3

It is a rational number.

c) 2-√5

It is a irrational number

d)√25 =5

It is a rational number

e) 2√7 x 7√7 = 2 x 7 x 7

                      =98

It is a rational number

Therefore, option C 2 - √5 is a irrational number.

#SPJ3

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