Question

1=
From the sum of 3x - y +11 and-y-11 subtract 3x-y-1.
2=If Z = 5 find the value of Z-5 (z - 6)​

Answer 1

From the sum of

(1).......3x-y+11 and -y-11 and then subtraction 3x-y-11

$= > (3x - y + 11) + ( - y - 11) - (3x - y - 11) \\ \\ = > 3x - y + 11 - y - 11 - 3x + y + 1 1\\ \\ = > - y + 11$

(2)

If z=5

Find value of z-5(z-6)

$z = > 5 \\ \\ = > z - 5(z - 6) \\ \\ = > 5 - 5(5 - 6) \\ \\ = > 0( - 1) \\ \\ = > 0$

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