Question

1. From the sum of 6a + 4b and 7a + 3b then

subtract 3a – 3b.

2. What should be added to a + 2b + 3x to get

3a + 2b + c.

3. Six times a number subtract from 40 gives 4. Find

the number.​

Answer 1

Answer:

(1)'-. 10a + 4b

(2) :- 2a + c - 3x

(3):- Let the number be 'x'

according to the question,

40 - 6x = 4

=> 6x = 36

=> x = 6

Hence the required number is 6

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Answer 2

Answer:

i can't understand that question

Step-by-step explanation:

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