Question

1) from the top of a 9 metres high building ab, the angle of elevation of the top of a tower cd is 30 and the angle of depression of the foot of the tower is 60. What is the height of the tower?

Answer 1

Step-by-step explanation:

Let distance between tower and building be y metre.

Height of tower = 9 + x metres.

Consider theta = 60 °

tan 60° = height of building / distance between tower and building

√3 = 9/y

∴y = 9/√3 = 3√3 m

Now, consider theta = 30°

tan 30° = part of tower whose height is unknown (∵ x )/distance between tower and building

1/√3 = x/y

1/√3 = x/3√3

∴x=3√3/√3 = 3 metres.

∴Total height of tower = x + 9 = 3 + 9 = 12 metres.

Hope it helps!!!

Answer 2

Answer:

The height of the tower will be 12m.