1 g equivalent of Na metal is formed from
electrolysis of fused NaCl. Number of moles of Al
formed by the same current from fused Na 3AlF6 will
be
(a) 1
(b) 3
(c) 1/3 (d) 2
Answers
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1
Answer:
answer is --- (c) 1/3
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NaCl is electrolysed to form Na+ and Cl- ions given by the equation:
Na+ + Cl- ----> NaCl
We know that 96,500 coulombs of electricity is required to liberate 1 mol of Na+ or 23 gm equivalents of Na+.
Therefore, 1 gm equivalent of Na+ would be liberated by 96500/23 Coulombs of electricity = 4195 Coulombs
Now, the amount of electricity used is the same in the electrolysis of Na3AlF6.
No. of moles of electrons = 4195 coulombs X One mole of electrons / 96, 500 Coulombs= 0.0434 moles of e-
We know that 1 Al3+ takes 3 e- --> to form Al metal
So, 0.0434 moles of e- X 1 mole Al / 3 mole e- = 0.0145 moles of Al
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