1 g equivalent of Na metal is formed from electrolysis of fused NaCl . moles of Al formed from fused Na3AlF6 will be. when same charge used in electrolysis of molten NaCl is crossed through molten Na3AlF6
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NaCl is electrolysed to form Na+ and Cl- ions given by the equation:
Na+ + Cl- ----> NaCl
We know that 96,500 coulombs of electricity is required to liberate 1 mol of Na+ or 23 gm equivalenets of Na+.
Therefore, 1 gm equivalent of Na+ would be liberated by 96500/23 Couloms of electricity = 4195 Coulombs
Now, the amount of electricity used is the same in the electrolysis of Na3AlF6.
No. of moles of electrons = 4195 coulombs X One mole of electrons / 96, 500 Coulombs= 0.0434 moles of e-
We know that 1 Al3+ takes 3 e- --> to form Al metal
So, 0.0434 moles of e- X 1 mole Al / 3 mole e- = 0.0145 moles of Al
Hope this answered your question...!!
Na+ + Cl- ----> NaCl
We know that 96,500 coulombs of electricity is required to liberate 1 mol of Na+ or 23 gm equivalenets of Na+.
Therefore, 1 gm equivalent of Na+ would be liberated by 96500/23 Couloms of electricity = 4195 Coulombs
Now, the amount of electricity used is the same in the electrolysis of Na3AlF6.
No. of moles of electrons = 4195 coulombs X One mole of electrons / 96, 500 Coulombs= 0.0434 moles of e-
We know that 1 Al3+ takes 3 e- --> to form Al metal
So, 0.0434 moles of e- X 1 mole Al / 3 mole e- = 0.0145 moles of Al
Hope this answered your question...!!
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