Question

1 g H2 gas expand at STP to occupy double of its original volume what is work done in this process

Answer 1

Work done during expansion is = - P dV

Also, PdV = nRT

n = 1/2 = 0.5mol

T = 273 K

R = 2 Cal/K

Work done = nRT
= 0.5 x 2 x 273
= 273 cal

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Answer 2

Work done = PdV= nRT

T =273

R= 2  cal/k

n for Hydrogen gas =1/2 = 0.5

 

Work done = 273 x 0.5 x 2 cal = 273 cal 

Temperature is constant and pressure too so we cannot decide the process is isothermal or isobaric.

You need to mention both until they give you another condition.