Question

1 g of dibasic acid is completely neutralized with 100 ml of 0.5 N NaOH solution what is the molar mass of acid?
(1) 20
(2) 30
(3) 40
(4) 50
Step by step ans plz...

Answer 1

Answer:40

Explanation:

Normality of NaOH= 0.5 N

Volume= 100ml

We know

Normality = Moles/Volume(in litre)

∴ Moles= Normality × Volume(in litre)

⇒ Moles= 0.5 × 100/1000 (Convert ml in l)

⇒ Moles= 0.05

Acid is Dibasic

⇒ 1 mole of this acid will neutralise 2 moles of NaOH

∴ Moles of acid required to neutralise 0.05 moles of NaOH = 1/2×0.05= 0.025 moles

∴ Molar Mass of Acid= Given Mass/Moles

⇒ Molar mass= 1/0.025 = 40.

Answer 2

Answer:

40

Explanation:

with 100 ml of 0.5 N NaOH solution what is the molar mass of acid?

(1) 20

(2) 30

(3) 40

(4) 50

Step by step ans plz...