1 g of H2 at 30°C is mixed with 14 g of N2 at 40°C.
Neglecting the vibrational mode, the temperature of
the mixture is
(1) 32°C
(2) 35°C
(3) 34°C
(4) 38°C
Answer=(2)
Answers
Answered by
68
Answer:
Explanation:
No of moles =given mass/mol.mass
No of moles of H2=1÷2=0.5
No of moles of N2=14÷28=0.5
Since both the molecules have same no of moles,their resulting temperature will the average of both the temperatures.
Therefore,
=30+40÷2
=70÷2
=35°C
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Answered by
24
(2) 35°C
Explanation:
Moles of :-
Mass = 1 g
Molar mass of = 2 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of :-
Mass = 14 g
Molar mass of = 28 g/mol
The formula for the calculation of moles is shown below:
Thus,
Since, both the moles are equal, the temperature will average out.
Thus, Temperature of the mixture:-
The answer is:- (2) 35°C
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