Physics, asked by roysahabji, 1 year ago

1 g of H2 at 30°C is mixed with 14 g of N2 at 40°C.
Neglecting the vibrational mode, the temperature of
the mixture is
(1) 32°C
(2) 35°C
(3) 34°C
(4) 38°C
Answer=(2)​

Answers

Answered by alisjohnny3
68

Answer:

Explanation:

No of moles =given mass/mol.mass

No of moles of H2=1÷2=0.5

No of moles of N2=14÷28=0.5

Since both the molecules have same no of moles,their resulting temperature will the average of both the temperatures.

Therefore,

=30+40÷2

=70÷2

=35°C

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Answered by mergus
24

(2) 35°C

Explanation:

Moles of H_2:-

Mass = 1 g

Molar mass of H_2 = 2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1\ g}{2\ g/mol}

Moles_{H_2}= 0.5\ mol

Moles of N_2:-

Mass = 14 g

Molar mass of N_2 = 28 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{14\ g}{28\ g/mol}

Moles_{N_2}= 0.5\ mol

Since, both the moles are equal, the temperature will average out.

Thus, Temperature of the mixture:-T=\frac{30+40}{2}\ ^0C=35\ ^0C

The answer is:- (2) 35°C

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