Question

1 g of metal combines with 8.89 g of bromine. equivalent weight of metal is nearly

Answer 1

Answer : The equivalent weight of metal is, 8.987 g

Solution : Given,

Mass of metal = 1 g

Mass of bromine = 8.89 g

Molar mass of bromine = 79.9 g/mole

The equivalent weight of the metal is the number of parts by mass of metal that combines with 79.9 parts by mass of bromine.

As, 1.0 g of metal combines with 8.89 g of bromine.

So, the mass of metal that combines with 79.9 g of bromine = $\frac{1}{8.89}\times 79.9=8.987g$

Therefore, the equivalent weight of metal is, 8.987 g

Answer 2

Answer:

Answer : The equivalent weight of metal is, 8.987 g

Solution : Given,

Mass of metal = 1 g

Mass of bromine = 8.89 g

Molar mass of bromine = 79.9 g/mole

The equivalent weight of the metal is the number of parts by mass of metal that combines with 79.9 parts by mass of bromine.

As, 1.0 g of metal combines with 8.89 g of bromine.

So, the mass of metal that combines with 79.9 g of bromine = \frac{1}{8.89}\times 79.9=8.987g

8.89

1

×79.9=8.987g

Therefore, the equivalent weight of metal is, 8.987 g