Question

1 g of Mg is burn with 0.56 g O2 in a closed vessel which reactant is left in excess and how much​

Answer 1

Explanation:

2Mg+O2= 2MgO

2mol Mg = 1molO2

means 32 g O2= 24 g Mg

or, 0.56gO2 =( 24/32)×(0.56) g = 0.42Mg

hence,Mg is left in excess and the amount left = (1-0.42)g = 0.58g Mg