Question

1 Given 3 (log 5 - log 3) - (log 5 - 2 log 6) = 2 - log n, find n.​

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11th

Applied Mathematics

Logarithm and Antilogarithm

Determination of Logs and Anti logs

Given 3 ( log 5 - log3 )...

Maths

Given 3(log5−log3)−(log5−2log6)=2−logn, Find n .

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Given :

3(log5−log3)−(log5−2log6)=2−logn

Let us simplify the given expression to find n,

3log5−3log3−log5+2log6=2−logn

2log5−3log3+2log6=2(1)−logn

log5

2

−log3

3

+log6

2

=2log10−logn[Since,1=log10]

logn=−log25+log27−log36+log100

=(log100+log27)−log5+log36)

=log(100×27)−log(25×36)

=log(100×27)−log(25×36)

=log(100×27)/(25×36)

logn=log3

n=3