Question

1. Given f (2 x + 5 ) = 6x + 7,
a. Find the formula of f(3p)
b. Find the value of f (15)

2. Given f ( x ) = ax + b , f ( -2 ) = 1 and f ( 3 ) = 11
calculate the value of 4f(3) – f(-2) + 2f(-1)

Answer 1

Answer:

x= 0.73 or x= -1.93

2. b^2 - 4ac = 0 for equal roots

6^2 - 4 x 5 x (-d) = 0

36 + 20d=0

20d= -36

d= -36/20 = 1 4/5

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

i) x

2

−2x−8

Factorize the equation, we get (x+2)(x−4)

So, the value of x

2

−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.

Therefore, the zeros of x

2

−2x−8 are -2 and 4.

Now,

⇒Sum of zeroes =−2+4=2=−

1

2

=−

Coefficient of x

2

Coefficient of x

⇒Product of zeros =(−2)×(4)=−8 =

1

−8

=

Coefficient of x

2

Constant term

(ii) 4s

2

−4s+1

Factorize the equation, we get(2s−1)(2s−1)

So, the value of 4s

2

−4s+1 is zero when 2s−1=0,2s−1=0