Question

1) Given: O is the centre of
circle
ZBCO = mº. ZBAC = nº
Find : The value of m+n​

Answer 1

m° + n° = 90°

Step-by-step explanation:

See the attached diagram.

Here, ∠ BOC = 2 × ∠ BAC = 2n° {Given that ∠ BAC = n°}

Now, Δ OBC is an isosceles triangle as BO = CO = Radius of the circle.

So, ∠ OBC = ∠ OCB = m° {Given that ∠ BCO = ∠ OCB = m°}

Now, from Δ OBC,

∠ OBC + ∠ OCB + ∠ BOC = 180°

⇒ m° + m° + 2n° = 180°

⇒ 2(m° + n°) = 180°

⇒ m° + n° = 90° (Answer)