1.
Given that A+B+C =0. Out of three vectors, the two are equal in magnitude and the
magnitude of third vector is 2 times that of either of the two having equal magnitude. Then
find the angles between vectors
(A) 90°,450,45° (B) 90°,135,135 (C) 90°, 60°,300 (D) 60°, 60°, 60°
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Step-by-step explanation:
From polygon law, three vectors having summation zero should form, a closed polygon(triangle). Since, the two vectors are having same magnitude and the third
vector is √2 times that of either of two having equal magnitude, i.e., the triangle should be right angled triangle.
Angle between A and B, α=90^o
Angle between B and C, β=135^o
Angle between A and C, γ=135^o .
hope it helps you
please make my answer as Brillant and follow
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