Question

1. Given that HCF(27, x) = 9 and
LCM(27, x) = 459, find the value
of x.​

Answer 1

Answer:

x= 153

Step-by-step explanation:

We know... LCM(a,b)* HCF(a,b) = a*b

THEREFORE, LCM(27,x)*HCF(27,x)=9*459

Therefore, 27x=4131..... which gives

x=153

Thank you...