Question

1 gm mixture of caco3 and NaCl reacts completely with 120 ml of 0.1 N hcl. The percent of NaCl is

Answer 1

Answer:

The percentage mass of Sodium Chloride is 40%.

Explanation:

tep 1 : Write down the relevant equations for the reaction.

In the given reaction NaCl does not react with HCl.

Therefore, the reaction between HCl and CaCO3 is given by :

CaCO3 + 2HCl —> CaCl2 + CO2 + H2O

The mole ratio is :

1 : 2

For every mole of Calcium Carbonate there are 2 reacting moles of Hydrochloric acid.

Step 2 : Calculate the moles of HCl in 120 ml

120/1000 × 0.1 = 0.012 moles

Since the mole ratio is 1 : 2

The moles of Calcium carbonate in the reaction is given by :

= 0.012/2 = 0.006 moles

Step 3 : Calculate the molar mass of Calcium Carbonate and the mass of Calcium Carbonate.

Molar mass of CaCO3 = 40 + 12 + 16 × 3 = 100

Mass = molar mass × moles

= 100 × 0.006 = 0.6 grams

Step 4 : Calculate the mass of Sodium Chloride from the total mass of the mixture.

Mass of Sodium Chloride = 1 - 0.6 = 0.4 grams

Step 5 : Calculate the percentage Mass of Sodium Chloride.

= 0.4/1 × 100 = 40%

Answer 2

Answer:

40%

Explanation:

Check the photo for solution