1 gm of metal nitrate gave 0.86 gm of metal sulphate calculate eq weight of metal
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Answered by
4
M(NO3)n --> M2(SO4)n
as n = Valency of metal
gm eq. M(NO3)n = gm eq. of M2(SO4)n
1/E(M) +E(NO3-) = 0.86/E(M) +E(SO4--)
=) E = 38
as n = Valency of metal
gm eq. M(NO3)n = gm eq. of M2(SO4)n
1/E(M) +E(NO3-) = 0.86/E(M) +E(SO4--)
=) E = 38
Answered by
1
M(NO3)n --> M2(SO4)n
as n = Valency of metal
gm eq. M(NO3)n = gm eq. of M2(SO4)n
1/E(M) +E(NO3-) = 0.86/E(M) +E(SO4--)
=) E = 38
as n = Valency of metal
gm eq. M(NO3)n = gm eq. of M2(SO4)n
1/E(M) +E(NO3-) = 0.86/E(M) +E(SO4--)
=) E = 38
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