Question

1. Graham's Law of Effusion: 8.378 x 104 mol of an unidentified gaseous substance effuses through a tiny hole in 86.98
under identical conditions: 1.740 x 10 mol of argon gas takes 81.3 s to effuse.
a) What is the molar mass of the unidentified substance in grams/mol?
b) What is the molecular formula of the substance?
c) Under identical conditions, how many moles of ethane (C2Ha) gas would effuse in 91.0 s?
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Answer 1

Answer:

a,b,c

Explanation:

a) What is the molar mass of the unidentified substance in grams/mol?

b) What is the molecular formula of the substance?

c) Under identical conditions, how many moles of ethane (C2Ha) gas would effuse in 91.0 s?

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