Question

1 gram of a gas at 7 degree Celsius and 2 atmosphere pressure occupies a volume of 410 ml determine the molar mass of the gas are is equal to 0.082 atmosphere /mole/k​

Answer 1

Explanation:

Mass M: 1 g

Pressure P = 2 atm

Volume V = 410/1000=0.410 L

Gas Constant R=0.082 L atm K−1mol−1

Temperature T= 7°C +273.15 = 280 K

Now we know,

PV=nRT

n = PV/RT

n = 2*.410/.082*280

n = 10/280

Molar mass = grams /mol

= 1/(10/280)

= 280/10 = 28 g/mol