1 gram of a substance when dissolved in 100 gm of water boiled at 100.307 degree celsius.the molal elevation constant for water o.52 k kg. Calculate the molar mass of the substance
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Answer:
Explanation:
Δt = kb *m
100.307-100= 0.52* 1/ M * 0.1
m= 0.52/ 0.1*0.307
= 16.94 g
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