Question

1 gram of hydrogen combines with 15.88 gram of sulphur. 1 gram of hydrogen combines with 7.92 gram of oxygen. 8 gram of sulphur combines with 7.92 gram of oxygen show that these data illustrate the law of reciprocal proportions

Answer 1

The law of the reciprocal :

The weights of two or more different elements which separately combines with a fixed weight of another element are either the same as or simple multiples of the weights of these elements when they combine among themselves.

HS : Hydrogen Sulphur

1 gram 15.88 gram

HO : Hydrogen Oxygen

1 gram 7.92 gram

The ratio of different weights of Oxygen (7.92) and Sulphur (15.88) Combining with the same weight of hydrogen is :

Oxygen : Sulphur

Approximately : 8 : 16 = 1 : 4

We also have :

SO : Sulphur Oxygen

8 7.92

The ratio of hydrogen(1) and Sulphur (8) reacting with equal weights of Oxygen is :

Hydrogen : Sulphur

1 : 8

From this we can see that the ratio of sulphur in this second ratio is a multiple of the first ratio.

Therefore the law of reciprocal and proportions has been illustrated.

Answer 2

Hey dear,

★ Law of reciprocal proportions -
It states that if two different elements combine separately with the same weight of a third element, the ratio of the masses in which they do so are either the same or a simple multiple of the mass ratio in which they combine.

★ Illustration -
In H2S H:S = 1:15.88
In H20 H:O = 1:7.92
In SO2 S:O = 8:7.92

Ratio of H:S to H:O in H2S to H2O is 1 : 2.

Ratio of O:H to O:S in H2O to SO2 is 8 : 1.

This shows that ratio of masses in one compound is simple multiple of the same in other compound.

Hope this helps you...