Question

1 gram of metal combines with 44.6 ml of oxygen to form oxide at stp the equivalent weight of the metal is

Answer 1

OR

22400 ml at STP = 1 mole of oxygen = 32 g 46.6 ml at STP = 3222400 × 46.6 = 0.06657 g of oxygen0.06657 g of oxygen combines with 0.1 g of the metalSo 8 g of oxygen combines with = 0.10.06657 × 8 = 12.02 gEquivalent weight of the metal = 12.02 g