Question

1 gram of pure calcium carbonate was found to require 50ml of dilute hcl for complete reaction

Answer 1

Given 1 gram of pure calcium carbonate was found to require 50ml of dilute hcl for complete reaction

So given one gram of pure calcium carbonate requires 50 ml of dilute hydrochloric acid.

So Normality is weight of calcium carbonate / masss /volme of solution

We know volume of hydrochloric acid = 50 ml = 0.05 l

    = 1/50 /0.05

= 1/50 x 1/0.05

= 1/2.5

= 0.4 N

Calcium carbonate when combined with hydrochloric acid gives calcium chloride, water and carbon dioxide.

   

Answer 2

Answer:

0.4N

Explanation:

= (Wt of CaCO3/eq mass)/vol of CaCO3 in lit

= (1/0.5)/50

= 0.4N