Question

1. hammer of mass 500 gram, moving at 50 metre per second, strikes and nail. The nails stop the hammer in very short time of 0.01 second. What is the force of the nail on the hammer?​

Answer 1

Given-

Mass of hammer= 500g =0.5kg

initial velocity of moving hammer= 50m/s

final velocity of moving hammer = 0m/s

Time taken by nail to stop hammer = 0.01s

To find-

Force

Solution-

Force = mass×acceleration

Acceleration = change in velocity/time

So

F = m×(v-u)/t

F= 0.5×(0-50)/0.01

F= -2500N

Thus required force is -2500 Newton.

Answer 2

Solution:

Given:

=> Mass (m) = 500 g = 0.5 kg

=> Initial velocity (u) = 50 m/s

=> Time (t) = 0.01 sec

To Find:

=> The force of the nail on the hammer.

Formula used:

$\sf{\implies F=\dfrac{m(v-u)}{t}}$

So,

$\sf{\implies F=\dfrac{m(v-u)}{t}}$

Put the values in the formula,

$\sf{\implies \dfrac{0.5(0-50)}{0.01}}$

$\large{\boxed{\boxed{\green{\sf{\implies Force = -2500\;N}}}}}$

The force is negative means that the force of nail on the hammer is acting in the direction opposite to that of hammer.