1) HCF is always______
a)multiple of LCM
b)factor of LCM
c)divisible by LCM
d)a and c both
Answers
Answered by
0
Answer:
c. divisible by LCM.
this is the right answer for this question.
Answered by
0
Answer:
Step-by-step explanation:
The correct answer is (b) because HCF < LCM
Also HCF x LCM = Number 1 x Number 2
We can also say that HCF contains the intersection of the two sets of number containing prime factors while LCM is union. We also know that Intersection of two sets is always a subset of union of two sets
Similar questions