Question

1. How are the following ethers prepared by Williamson's synthesis (1) Diethyl ether (2) Ethyl methyl ether (3)
Ethyl phenyl ether?​

Answer 1

Answer:

answer 1 diethyl ether

hope it's help you

Answer 2

Preparation of ethers from Williamson's Synthesis

Explanation:

Williamson's synthesis is a reaction of alkyl halide with an alkoxide to produce ethers.

Both simple(symmetrical) and mixed(unsymmetrical) ethers can be made.

General reaction:

$RX + NaOR --> ROR+ NaX$

(1) Diethyl ether

Reaction of ethyl chloride with sodium ethoxide yields Diethyl ether( simple ether) and sodium chloride salt.

$CH_{3}CH_{2}Cl + CH_{3}CH_{2}ONa --> CH_{3}CH_{2}OCH_{2}CH_{3} + NaCl$

(2) Ethyl methyl ether

Methyl chloride when reacts with sodium ethoxide, forms ethyl methyl ether(mixed ether) with sodium chloride as a by-product.

$CH_{3}Cl + CH_{3}CH_{2}ONa --> CH_{3}OCH_{2}CH_{3} + NaCl$

(3)  Ethyl phenyl ether

Reaction of ethyl chloride with sodium phenoxide will form an ethyl phenyl ether and a by-product.

$CH_{3}CH_{2}Cl + C_{6}H_{5}ONa --> CH_{3}CH_{2}OC_{6}H_{5} + NaCl$