Question

1.
How far should the supports be if the bridge is to support 6.5 tons?
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Answer 1

6.70 meters apart.

Explanation:

t(d)= (12.5/d)3

3 Vt= 12.5/d

d=

$12. {5}^{3}$

✓t

The inverse function is d(t) = 12.5 Vt

Evaluate the function at t = 6.5: d (6.5) = 12.53 16.5: = 6.70.