Question

1. How many gram of hydrogen chloride, HCl are
required to prepare 4 litre of 5 M HCl in water?​

Answer 1

Answer:

730 g

Explanation:

Given,

Molarity = 5M

Volume = 4L

Moles of HCl =molarity *volume

=5*4 =20 moles

1 mole of HCl =36.5 g

For 20 moles = 36.5 * 20

= 730 g