1. How many liters of F2 at STP are needed with 4.00L of H2 also measured at STP in following reaction:
H2 (g) + F2 (g) - 2HF(g)
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Given Reaction⇒
H₂ + F₂ --------→ 2HF
From this reaction,
1 mole of hydrogen reacts with the 1 mole of flourine.
We know, one mole of any gas at S.T.P. occupies the volume of 22.4 liter.
∴ 22.4 liter of the hydrogen reacts with the 22.4 liter of flourine to from hydrogen flouride.
∴ 1 liter of the H₂ reacts with the 1 liter of the F to form HF.
∴ 4 liter of H₂ reacts with the with the 1 × 4 = 4 liter of thr F to form HF.
Hence, Volume of the Flourine (F) needed in the reaction is 4 liter.
Hope it helps.
H₂ + F₂ --------→ 2HF
From this reaction,
1 mole of hydrogen reacts with the 1 mole of flourine.
We know, one mole of any gas at S.T.P. occupies the volume of 22.4 liter.
∴ 22.4 liter of the hydrogen reacts with the 22.4 liter of flourine to from hydrogen flouride.
∴ 1 liter of the H₂ reacts with the 1 liter of the F to form HF.
∴ 4 liter of H₂ reacts with the with the 1 × 4 = 4 liter of thr F to form HF.
Hence, Volume of the Flourine (F) needed in the reaction is 4 liter.
Hope it helps.
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